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using series/parallel resistance combination, find the equivalent resistance seen by the source in the given circuit. find the overall absorbed power by the resistor network. assume v = 740 v.

User Qamnott
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Final answer:

The question involves calculating equivalent resistance and power in both series and parallel circuits by applying Ohm's law and principles of electric circuits.

Step-by-step explanation:

The question asks about finding the equivalent resistance seen by the source in a circuit and calculating the overall absorbed power by the resistor network. To do so, one must understand the principles of series and parallel circuits in electricity. Assuming V represents the voltage source and R1, R2, etc., represent resistances at different points in the circuit, the equivalent resistance in a parallel connection (Rp) can be found using the formula 1/Rp = 1/R1 + 1/R2 + 1/R3 and so on. For power calculations, the total power dissipated can be calculated using the formula P = V2/R for each resistor and then summing up to find the total power. The power output of the source is equal to the product of voltage and total current supplied by the source, P = IV. After calculating, it's crucial to verify that the power supplied by the source equals the total power dissipated by the resistors.

User Pankaj Wadhwa
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