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Three products with the molecular formula C₆H₄IBr form when iodobenzene is treated with bromine, Br₂, in the presence of FeBr₃ as a catalyst. Draw a structural formula for each product.

User Dat Nguyen
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Final answer:

When iodobenzene is treated with bromine in the presence of FeBr3 as a catalyst, three products are formed - 1-bromo-2-iodobenzene, 1-bromo-4-iodobenzene, and 1-bromo-3-iodobenzene.

Step-by-step explanation:

Benzene, C6H6, has the molecular formula C6H4IBr. When iodobenzene is treated with bromine, Br2, in the presence of FeBr3 as a catalyst, three products are formed.

The structural formulas for each product can be drawn as follows:

1. The first product is 1-bromo-2-iodobenzene, with the bromine and iodine substituents adjacent to each other:

2. The second product is 1-bromo-4-iodobenzene, with the bromine and iodine substituents one carbon apart:

3. The third product is 1-bromo-3-iodobenzene, with the bromine and iodine substituents two carbons apart:

User TKrugg
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