Final answer:
When iodobenzene is treated with bromine in the presence of FeBr3 as a catalyst, three products are formed - 1-bromo-2-iodobenzene, 1-bromo-4-iodobenzene, and 1-bromo-3-iodobenzene.
Step-by-step explanation:
Benzene, C6H6, has the molecular formula C6H4IBr. When iodobenzene is treated with bromine, Br2, in the presence of FeBr3 as a catalyst, three products are formed.
The structural formulas for each product can be drawn as follows:
1. The first product is 1-bromo-2-iodobenzene, with the bromine and iodine substituents adjacent to each other:
2. The second product is 1-bromo-4-iodobenzene, with the bromine and iodine substituents one carbon apart:
3. The third product is 1-bromo-3-iodobenzene, with the bromine and iodine substituents two carbons apart: