88.3k views
0 votes
a 1-inch diameter, 1-foot long rod is subjected to a tensile force of 2000 lb. the rod is made of 6061-t6 aluminum with e = 10,000 ksi, v = 0.33, and g = 3770 ksi.

User Josivan
by
7.7k points

1 Answer

4 votes

Final answer:

The question is about calculating the mechanical stress and elongation of a metallic rod subjected to a tensile force, involving knowledge of materials engineering and solid mechanics, particularly the elastic properties of the materials defined by Young's modulus, Poisson's ratio, and shear modulus.

Step-by-step explanation:

The question at hand involves the application of mechanical principles to calculate the stress and elongation of a rod subjected to a tensile force. Specifically, it concerns with the elastic deformation of materials under a load, including the relations involving Young's modulus, Poisson's ratio, and shear modulus. Being in the context of a 6061-T6 aluminum rod and a steel rod, the problems incorporate concepts from materials engineering and solid mechanics.

To find the tensile stress in the rod supporting a platform, we use the formula:

  1. Calculate the force due to the weight of the platform using the equation F = mg, where m is the mass of the platform and g is the acceleration due to gravity.
  2. Determine the cross-sectional area of the rod.
  3. Apply the stress formula σ = F/A, where σ is the stress, F is the force, and A is the cross-sectional area.

To calculate the elongation of the rod, the steps are:

  1. Utilize Hooke's Law for linear elastic deformation, which states that δL = (FL) / (AE), where δL is the elongation, F is the force applied, L is the original length, A is the cross-sectional area, and E is the Young's modulus.

It's important to note that additional calculations may be required if the rod is subjected to other forces or conditions, such as thermal expansion or different types of loading. The given problems also touch upon the fracture point of materials, which relates to the concept of breaking stress.

User Barri
by
8.3k points