Final answer:
The question seems to confuse stability concepts from dynamic systems with solving algebraic equations. Stability terms are not applicable to simple linear equations. The provided equations are straightforward and solved for 'x', resulting in specific values for each case.
Step-by-step explanation:
The question is asking to determine whether certain mathematical models are stable, unstable, or neutrally stable. Upon reviewing the provided equations, it seems there might be a misunderstanding because the question does not include mathematical models typically associated with stability (such as systems of differential equations). Instead, the question lists several algebraic equations.
For simple algebraic equations or linear equations, we do not use terms like 'stable' or 'unstable,' which are more applicable to dynamic systems. However, to answer the question based on the given equations (assuming they are meant to be mathematical expressions), we will simply solve for 'x' which the student has attempted in equations a through f. Here is the correction for each:
- a. This equation simplifies to -2x = 7, which yields x = -7/2 or -3.5.
- b. This corrects to -6x = 50, resulting in x = -50/6 or approximately -8.33.
- c. The equation simplifies to -16x = 68, so x = -68/16 or -4.25.
- d. No correction needed; x = 3 is already in simplified form.
- e. The equation corrects to 10x = 5, yielding x = 0.5.
- f. Similarly, 17x = 7 translates to x = 7/17 or approximately 0.41.
In each case, we find the value of 'x' that satisfies the equation.