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Assume logbx=0.25 and logby=0.34. Evaluate the following expression. logb(x/y).

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Final answer:

To evaluate logb(x/y), subtract the logarithms of the two numbers. In this case, logb(x/y) = 0.25 - 0.34 = -0.09.

Step-by-step explanation:

To evaluate logb(x/y), we can use the property of logarithms that states the logarithm of a quotient of two numbers is equal to the difference of the logarithms of the two numbers. So, logb(x/y) = logbx - logby.

Given that logbx = 0.25 and logby = 0.34, we substitute these values into the equation: logb(x/y) = 0.25 - 0.34.

Simplifying the expression gives logb(x/y) = -0.09.

User Nilesh Rathore
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