Question

a baseball thrown at an angle of 60.0 ∘ above the horizontal strikes a building 17.0 m away at a point 6.00 m above the point from which it is thrown. ignore air resistance.

Answer 1

To solve this problem, we need to calculate various parameters such as the time of flight, initial horizontal velocity, vertical component of velocity, and the velocity just before the ball hits the ground.

Step-by-step explanation:

To solve this problem, we can break it down into two separate motions: the horizontal motion and the vertical motion.

Horizontal Motion:

1. Calculate the time of flight for the horizontal motion using the formula t = d/v, where d is the horizontal distance and v is the horizontal component of the velocity.
2. Since the ball is thrown horizontally, the horizontal component of the velocity is equal to the initial velocity.

Vertical Motion:

1. Calculate the vertical displacement using the formula h = ut + (1/2)gt^2, where h is the vertical displacement, u is the initial vertical velocity, g is the acceleration due to gravity, and t is the time of flight.
2. Substitute the given values into the equation and solve for the initial vertical velocity.

Thus, the time of flight, initial horizontal velocity, vertical component of velocity, and the velocity just before hitting the ground can be calculated using the given information.