Question

What is the slope of the line 6x+23y=1
?

Answer 1

The slope of the line represented by the equation 6x+23y=1 is -6/23, found by rearranging the equation into the slope-intercept form.

Step-by-step explanation:

To find the slope of the line given by the equation 6x+23y=1, we need to rewrite it in slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept. The first step is to isolate y on one side of the equation.

Starting with 6x + 23y = 1, we subtract 6x from both sides to get 23y = -6x + 1. Next, we divide each term by 23 to solve for y, obtaining y = (-6/23)x + (1/23). Now the equation is in slope-intercept form, and we can see that the slope m is -6/23.

Therefore, the slope of the line 6x + 23y = 1 is -6/23.

Answer 2

To understand this line better, we should convert it to slope-intercept form.

`6x+23y=1\\6x-6x+23y=1-6x\\23y=-6x+1\\23y/23=-6x/23+1/23\\y=-\frac6{23}x+\frac1{23}`

As the standard for slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept, m = -6/23.