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Write the method is Even that returns true when its argument is even?

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Final answer:

To check if a number is even, a method can be defined that uses the modulo operator to check if the number is divisible by 2 without a remainder. It returns true if the number is even, and false otherwise.

Step-by-step explanation:

In mathematics, an even number is defined as a number that is divisible by 2 without leaving a remainder. Therefore, to write a method in a programming language that returns true when its argument is even, we can use the modulo operator (%) to check if the argument is divisible by 2.

If the remainder is 0, then the number is even and the method should return true. Otherwise, it should return false. Here's an example in Java:

public static boolean isEven(int n) {
return n % 2 == 0;
}

This method takes an integer argument n and returns true if n is even, and false otherwise.

User Dmitry Trofimov
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