Question

a capacitor of 5 mf charged to 1 kv is discharged through an inductor of 2 mh. the total resistance in the circuit is 5 mω.

Answer 1

The voltage induced in a coil can be calculated using the formula V = -L(dI/dt), where V is the voltage induced, L is the mutual inductance, and dI/dt is the rate of change of current.

Step-by-step explanation:

The voltage induced in a coil can be calculated using the formula:

V = -L(dI/dt)

Where V is the voltage induced, L is the mutual inductance, and dI/dt is the rate of change of current. In this case, the mutual inductance is given as 5.00 mH and the rate of change of current is 2.00 A switched off in 30.0 ms. Plugging these values into the formula, we get:

V = -(5.00 mH)(2.00 A / 30.0 ms) = -0.333 V

Therefore, the voltage induced in one coil when the current in the other is switched off is -0.333 V.