Question

calculate the ph of a 0.2 m acetate buffer (pka = 4.77) that contains twice as much acid as conjugate base.

Answer 1

The pH of a 0.2 M acetate buffer can be calculated using the Henderson-Hasselbalch equation. Given a pKa of 4.77 and twice as much acid as conjugate base, the pH is approximately 4.469.

Step-by-step explanation:

To calculate the pH of the acetate buffer, we need to consider the Henderson-Hasselbalch equation:

pH = pKa + log([Base]/[Acid])

Given that the pKa is 4.77 and the buffer contains twice as much acid as conjugate base, we can set up the equation as follows:

pH = 4.77 + log(1/2)

Simplifying, pH = 4.77 - log(2)

Calculating log(2), pH = 4.77 - 0.3010

Therefore, the pH of the acetate buffer is approximately 4.469.