Final answer:
The Lewis structures for C2H3Cl, C2HBrClF3, and C2Cl2F4 involve arranging the atoms with single bonds and then fulfilling the octets of surrounding atoms. For vinyl chloride, the structure is H2C=CHCl. Halothane is H2C-CBrClF3 with all three fluorines on the same carbon, and for C2Cl2F4, it's Cl2C-CF4 with each carbon bonded to two chlorides and four fluorines respectively.
Step-by-step explanation:
The question asks for the Lewis formula for each of the following organic molecules: C2H3Cl (vinyl chloride), C2HBrClF3 (halothane), and C2Cl2F4. Here's how you can approach drawing their Lewis structures:
- First, calculate the total number of valence electrons for each molecule.
- Draw a skeleton structure for the molecule, connecting atoms with single bonds.
- Complete the octets of the atoms bonded to carbon (bromine, chlorine, fluorine) by adding lone pairs of electrons.
- Place any remaining electrons on the carbons to fulfill their octet requirement, forming double bonds if necessary.
Vinyl chloride (C2H3Cl): H2C=CHCl
Halothane (C2HBrClF3): This anesthetic has all three fluorines bonded to the same carbon, so you would have H2C-CBrClF3 with the second carbon surrounded by three fluorines and a chlorine.
C2Cl2F4: This could be Cl2C-CF4 with each chlorine bonded to one carbon and the other carbon bonded to the four fluorines.