Question

Household bleach is typically a 6.00% solution of sodium hypochlorite and has a density of 1.08 g/mL. Using household bleach and saltwater of the same molarity, describe the quantities of each that would me needed to make 30 of a solution that contained 50% of the hypochlorite in household bleach.

Answer 1

To prepare 30 mL of a solution with 50% of the hypochlorite concentration in household bleach, one would mix 15 mL of household bleach with 15 mL of saltwater, assuming both solutions have the same concentration (6.00%).

Step-by-step explanation:

To make a 30 mL solution with 50% of the hypochlorite concentration in household bleach, we need to determine the mass of sodium hypochlorite (NaOCl) required, then calculate the volume of bleach and saltwater needed. First, calculate the mass of NaOCl in the original 6.00% household bleach for 30 mL of solution:

Mass of NaOCl = 30 mL × 1.08 g/mL × 0.06 = 1.944 g

For a 50% reduction, we need half of this mass:

Reduced Mass of NaOCl = 1.944 g × 0.5 = 0.972 g

Assuming the saltwater has the same 6.00% concentration of NaOCl, the required volume of bleach to get 0.972 g NaOCl is given by:

Volume of bleach = (0.972 g) / (1.08 g/mL × 0.06) = 15 mL

The remaining volume of the solution will be saltwater, which is 15 mL (since we need 30 mL in total). Therefore, the required quantities are 15 mL of household bleach and 15 mL of saltwater with the same molarity to achieve a 50% hypochlorite solution relative to household bleach.