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Suppose you have two small pith balls that are 5.5 cm apart and have equal charges of -33 nc?

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Final answer:

The Physics question asks for the calculation of the repulsive electrostatic force between two charged pith balls using Coulomb's Law. The example given demonstrates the importance of unit conversion for accurate computation of the force between charged bodies.

Step-by-step explanation:

The subject of this question is Physics, specifically concerning Coulomb's Law which describes the electrostatic interaction between electrically charged particles. To find the repulsive force between two pith balls that are 5.5 cm apart with equal charges of -33 nC, we would use Coulomb's formula: F = k * |q1*q2| / r^2, where F represents the force between the charges, k is Coulomb's constant (8.988 × 10^9 N m^2/C^2), q1 and q2 are the magnitudes of the charges, and r is the separation distance in meters. However, as this specific calculation is not provided, with regards to another example given in the reference which is between pith balls 8.00 cm apart with charges of -30 nC, the calculation process involves converting cm to m and then following the formula to find the electrostatic force. Remember that forgetting to convert cm to m will result in an incorrect answer as this affects the units of the formula resulting in the force.

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