Final answer:
When the reaction A + B is at equilibrium, the concentrations of reactants are A: 2 mM, B: 3 mM, and C: 9 mM. If we disturb the equilibrium by adding 0.50 moles of A to the mixture, the equilibrium will shift towards the right, forming more B.
Step-by-step explanation:
When the reaction A + B is at equilibrium, the concentrations of reactants are as follows:
- A: 2 mM
- B: 3 mM
- C: 9 mM
Now, if we disturb the equilibrium by adding 0.50 moles of A to the mixture, the equilibrium will shift towards the right, forming more B.
Let's assume that the equilibrium concentrations of A and B after the addition of A are 1.0 M each.
By using the ICE (Initial, Change, Equilibrium) analysis, we can determine the change in concentrations as the reaction proceeds.
Since the mole ratio of A:B is 1:1, as the concentration of A decreases by the amount x, the concentration of B increases by the amount x.