72.5k views
1 vote
When the reaction A + B is at equilibrium, the concentrations of reactants are as follows

A.2 mM
B.3 mM
C.9 mM

User Trelzevir
by
8.5k points

1 Answer

4 votes

Final answer:

When the reaction A + B is at equilibrium, the concentrations of reactants are A: 2 mM, B: 3 mM, and C: 9 mM. If we disturb the equilibrium by adding 0.50 moles of A to the mixture, the equilibrium will shift towards the right, forming more B.

Step-by-step explanation:

When the reaction A + B is at equilibrium, the concentrations of reactants are as follows:

  1. A: 2 mM
  2. B: 3 mM
  3. C: 9 mM

Now, if we disturb the equilibrium by adding 0.50 moles of A to the mixture, the equilibrium will shift towards the right, forming more B.

Let's assume that the equilibrium concentrations of A and B after the addition of A are 1.0 M each.

By using the ICE (Initial, Change, Equilibrium) analysis, we can determine the change in concentrations as the reaction proceeds.

Since the mole ratio of A:B is 1:1, as the concentration of A decreases by the amount x, the concentration of B increases by the amount x.

User Tesmojones
by
8.5k points