Final answer:
The enantiomeric excess (ee) of a mixture is 42%, which is the difference between the two enantiomers, calculated by subtracting the percent of the lesser enantiomer from the percent of the greater one.
Step-by-step explanation:
The enantiomeric excess (ee) of a mixture can be calculated by determining the difference in percentage between the two enantiomers. In this case, the mixture is composed of 29% of the (+) enantiomer and 71% of the (-) enantiomer. To find the enantiomeric excess (ee), one would subtract the percentage of the lesser enantiomer from the percentage of the greater enantiomer.
In the given mixture:
- Percentage of (-) enantiomer = 71%
- Percentage of (+) enantiomer = 29%
Calculating the enantiomeric excess:
- ee = %(-) - %(+)
- ee = 71% - 29%
- ee = 42%
Therefore, the enantiomeric excess of the mixture is 42%