Question

An ideal gas in a balloon is kept in thermal equilibrium with its constant-temperature surroundings. How much work is done by the gas if the outside pressure is slowly reduced, allowing the balloon to expand to 6.0 times its original size? The balloon initially has a pressure of 645 Pa and a volume of 0.10 m3. The ideal gas constant is R = 8.314 J/mol·K.

A) 120J
B) 6.0J
C) 390J
D) -330J

Answer 1

The correct answer is D) -330J. work done by the gas in expanding to 6 times its original size is -330J. gas can be calculated using the formula: Work = -PΔV where P is the pressure and ΔV is the change in volume. Given that the balloon expands to 6.0 times.

Step-by-step explanation:

The work done by the gas can be calculated using the formula: Work = -PΔV where P is the pressure and ΔV is the change in volume. Given that the balloon expands to 6.0 times its original size, the change in volume is:

ΔV = 6.0 * original volume - original volume = 6.0 * 0.10 m3 - 0.10 m3 = 0.5 m3.

Substituting the values into the formula, we get:

Work = -645 Pa * 0.5 m3 = -322.5 J.

the work done is negative, the correct answer is D) -330J. work done by the gas in expanding to 6 times its original size is -330J. gas can be calculated using the formula: Work = -PΔV where P is the pressure and ΔV is the change in volume. Given that the balloon expands to 6.0 times.