Final answer:
For a normal distribution n(97, 6), the maximum value of f(x) is reached at x=97, as this is the mean of the distribution where the curve's peak occurs.
Step-by-step explanation:
The student has asked about the value of x at which f(x) reaches a maximum for a normal distribution n(97, 6). For any normal distribution n(μ, σ), where μ is the mean and σ is the standard deviation, the maximum value of f(x) is always at x = μ. Therefore, for your specific normal distribution n(97, 6), the maximum value of f(x) occurs at x = 97. This is because the normal distribution is symmetrical around its mean, and the highest point on the curve, or the peak, is right at the mean value.