Question

A parallel plate capacitor consists of two plates, each with an area of 2.5 m², separated by 0.1 mm. What is the capacitance of the capacitor, in nF ?

Answer 1

The capacitance of the parallel plate capacitor is 22.1 nF.

Step-by-step explanation:

The capacitance of a parallel plate capacitor can be calculated using the formula C = ε₀ * (A/d).

Where C is the capacitance, ε₀ is the permittivity of free space, A is the area of each plate, and d is the distance or separation between the plates.

In this case, the area of each plate is given as 2.5 m² and the separation is given as 0.1 mm.

Using the value of ε₀ as 8.85 x 10⁻¹² F/m, we can substitute the given values into the formula to calculate the capacitance:

C = (8.85 x 10⁻¹² F/m) * (2.5 m²) / (0.1 x 10⁻³ m) = 2.21 x 10⁻⁸ F

To convert this value to nanofarads (nF), we can use the conversion:

1 nF = 10⁹ F

Therefore, the capacitance of the parallel plate capacitor is 22.1 nF.