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Draw the major organic product for each of the hydroboration-oxidation reactions?

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Final answer:

Hydroboration-oxidation is a two-step process that transforms alkenes into alcohols with anti-Markovnikov regioselectivity. The specific reaction conditions result in the addition of water across the double bond, producing an alcohol with the OH group on the less substituted carbon. The drawings must reflect the appropriate regiochemistry and, if applicable, stereochemistry.

Step-by-step explanation:

When tasked with drawing the major organic product for each of the hydroboration-oxidation reactions, you're generally being asked to illustrate the outcome of a specific type of addition reaction in organic chemistry. Hydroboration-oxidation is a two-step synthesis process that converts alkenes into alcohols through the action of borane (BH3) followed by hydrogen peroxide (H2O2) and sodium hydroxide (NaOH). Remember that in these reactions, the anti-Markovnikov addition of water across the double bond of alkenes occurs, resulting in the formation of an alcohol with the OH group attaching to the less substituted carbon atom.

In this context, you would use skeletal structures or full structural formulas to represent the starting alkene and the product alcohol. The structures should indicate the correct regiochemistry, which refers to the location of the OH group in the final alcohol product. Additionally, ensure that your drawings reflect proper stereochemistry if the reactant alkenes are capable of producing chiral alcohol products.

The exercises listed appear to cover various topics from nomenclature of organic compounds, stereochemistry of coordination compounds, and organic reaction mechanisms. Each of these topics requires specific drawing conventions and understanding of molecular structure to accurately depict the required chemical entities.

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