Final answer:
The heat absorbed by the water as it is heated from 21 °C to 85 °C is calculated using the formula Q = mcΔT, considering the mass of water, the specific heat capacity of water, and the change in temperature.
Step-by-step explanation:
To calculate the amount of heat absorbed by the water in a flask, we will use the specific heat capacity formula. This requires the mass of the water, the change in temperature, and the specific heat capacity of water. The specific heat capacity of water is approximately 4.18 J/g°C.
The formula to find out the heat absorbed (Q) is: Q = mcΔT, where m is the mass of the water, c is the specific heat capacity, and ΔT is the change in temperature. Here we have a mass of 8.0 × 10² g of water, a specific heat capacity of 4.18 J/g°C, and a temperature change (ΔT) from 21 °C to 85 °C, which is 85 °C - 21 °C = 64 °C.
The calculation would be: Q = (8.0 × 10² g) × (4.18 J/g°C) × (64 °C), which yields the amount of heat energy in joules. After solving this multiplication, we find the heat absorbed by the water.