Final answer:
When solid barium iodide is placed in water, it dissolves into barium ions and iodide ions, creating an aqueous solution of these individual ions without forming a precipitate.
Step-by-step explanation:
When solid barium iodide (BaI2) is put into water, it undergoes a process called dissolution where it dissociates into its constituent ions. This is not a precipitate-forming reaction, but rather just a physical process of a solid ionic compound dissolving in water. The balanced chemical equation for this process is:
BaI2(s) → Ba2+(aq) + 2I−(aq)
Here, the solid barium iodide separates into barium ions (Ba2+) and iodide ions (I−), both of which are hydrated and in aqueous form after the reaction.