Final answer:
The ratio of the acceleration due to gravity at the position of a satellite located 295 km above the earth's surface to the free-fall acceleration at the surface of the earth is less than 1.
Step-by-step explanation:
To find the ratio of the acceleration due to gravity at the position of a satellite located 295 km above the earth's surface to the free-fall acceleration at the surface of the earth, we can use the formula:
ratio = g_{satellite} / g_{earth_surface}
where g_{satellite} is the acceleration due to gravity at the satellite's position and g_{earth_surface} is the free-fall acceleration at the surface of the earth.
Since the acceleration due to gravity decreases with increasing distance from the earth's surface, g_{satellite} will be less than g_{earth_surface}. Therefore, the ratio will be less than 1.