Question

Please help if you could give answer and explanation i would be grateful

Answer 1

1. Only the fourth equation
`\(2Fe_(2)O_(3) + 3C \rightarrow 4Fe + 3CO_(2)\)` is unbalanced.

2. covalent, different, 1, 4, 1, 8, 2, and stable.

How did we arrive at these assertions?

1. To determine if the given chemical equations are balanced or unbalanced, we need to check whether the number of atoms of each element on the reactant side is equal to the number of atoms of the same element on the product side.

1.
`\(N_(2) + H_(2) \rightarrow 2NH_(3)\)`

- Nitrogen (N): 2 on both sides

- Hydrogen (H): 2 on both sides

- Balanced: Yes

2.
`\(2C_(2)H_(6) + 7O_(2) \rightarrow 4CO_(2) + 6H_(2)O\)`

- Carbon (C): 4 on both sides

- Hydrogen (H): 12 on both sides

- Oxygen (O): 14 on both sides

- Balanced: Yes

3.
`\(4ZnS + 6O_(2) \rightarrow 4ZnO + 4SO_(2)\)`

- Zinc (Zn): 4 on both sides

- Sulfur (S): 4 on both sides

- Oxygen (O): 14 on both sides

- Balanced: Yes

4.
`\(2Fe_(2)O_(3) + 3C \rightarrow 4Fe + 3CO_(2)\)`

- Iron (Fe): 4 on both sides

- Carbon (C): 3 on both sides

- Oxygen (O): 10 on both sides

- Unbalanced: No

5.
`\(C_(3)H_(8) + 5O_(2) \rightarrow 3CO_(2) + 4H_(2)O\)`

- Carbon (C): 3 on both sides

- Hydrogen (H): 8 on both sides

- Oxygen (O): 10 on both sides

- Balanced: Yes

So, only the fourth equation
`\(2Fe_(2)O_(3) + 3C \rightarrow 4Fe + 3CO_(2)\)` is unbalanced.

2. The bonds in methane are covalent because hydrogen and carbon have different electronegativity. Carbon bonds with four hydrogen atoms because hydrogen has 1 valence electron(s) and carbon has 4 valence electrons; so carbon shares 1 valence electron with each of the four hydrogen atoms to satisfy the necessary 8 valence electrons for carbon and 2 for hydrogen to become stable.