Question

Find the magnitude of the torque in foot-pounds at point p for the following lever:pq=9in. andf=5lb

a)4962ft-lb
b)-1582ft-lb
c)7122ft-lb
d)1582ft-lb

Answer 1

The magnitude of the torque at point p for the lever with arm PQ=9 inches and force F=5 pounds is 3.75 foot-pounds, which is not listed in the provided options.

Step-by-step explanation:

The student asked to find the magnitude of the torque in foot-pounds at point p for a lever, given that the lever arm PQ is 9 inches and the force applied is 5 pounds. Using the formula for torque, τ = r₁F, where r₁ is the distance from the pivot to the point where the force is applied, and F is the force. Here, we have r₁ = 9 inches = 0.75 feet (since there are 12 inches in a foot) and F = 5 pounds. The magnitude of the torque is thus calculated as:

τ = 0.75 feet * 5 pounds = 3.75 foot-pounds

Therefore, the correct answer is none of the provided options, and the correct magnitude of the torque is 3.75 foot-pounds. When providing answers that involve physical quantities, it's important to ensure that the units are consistent and converted appropriately.