Final answer:
The oxidation number of N in NaNO3 is +5.
Step-by-step explanation:
The oxidation number of N in NaNO3 is +5.
- First, we assign the oxidation numbers of the other elements in the compound. Sodium (Na) has an oxidation number of +1, and oxygen (O) has an oxidation number of -2.
- We know that the overall charge of NaNO3 is 0, so the sum of the oxidation numbers must equal 0.
- Let x be the oxidation number of N. Using the information above, we can set up the equation: +1 + x + (-2)(3) = 0.
- Simplifying the equation, we get +1 + x - 6 = 0.
- Solving for x, we find that the oxidation number of N in NaNO3 is +5.