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If a reaction mixture contains 2 moles of N₂ and 7 moles of H₂, what is the total number of moles of reactants?

1) 9 moles
2) 5 moles
3) 14 moles
4) Cannot be determined

User Jeff Morin
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1 Answer

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Final answer:

The total number of moles of reactants in a mixture containing 2 moles of N₂ and 7 moles of H₂ is 9 moles (2 moles of N₂ + 7 moles of H₂).

Step-by-step explanation:

If a reaction mixture contains 2 moles of N₂ and 7 moles of H₂, the total number of moles of reactants can be determined simply by adding these two amounts together, because the total moles of reactants is the sum of the individual moles of each reactant present in the mixture. In this case, you would calculate the sum as follows: 2 moles of N₂ + 7 moles of H₂ = 9 moles of reactants. Therefore, the correct answer is option 1) 9 moles. This calculation is based on the stoichiometry of the reaction, which in this case does not need to be taken into account because we are only asked to find the total moles of present reactants, not the reactants left after a reaction or the products formed.

User BananaNeil
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