The correct initial condition to impose alongside y(0) = -3, for a unique solution to the initial value problem is .
The initial value problem given is , with the initial condition . To fully determine the solution for this second-order differential equation, we need two initial conditions: one for the function itself, , and one for its first derivative, . The problem statement already gives us , which satisfies one initial condition. The additional initial condition needed is for , the derivative of y with respect to time at t=0, hence the correct answer is . This value ensures we can find a unique solution for the given differential equation that satisfies both initial conditions.
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