Final answer:
To find the magnitude of the average force in the x-direction that the particle exerts on the right-hand wall of the container as it bounces back and forth, we need to consider the concept of impulse.
Step-by-step explanation:
To find the magnitude of the average force in the x-direction that the particle exerts on the right-hand wall of the container as it bounces back and forth, we need to consider the concept of impulse. Impulse is the change in momentum of an object and is equal to the average force exerted on it multiplied by the time during which the force is applied. In this case, since the particle bounces off the wall and reverses its velocity, the change in momentum is equal to the initial momentum minus the final momentum. By calculating the impulse and dividing it by the time of collision, we can find the magnitude of the average force in the x-direction.
Keywords: average force, x-direction, particle, bounces back, impulse, momentum, velocity, collision