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show the maximum number of co60 nuclei occurs at t = 3.62 x 108 s. express your answer in seconds and again in years.

User Sqrepants
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Final answer:

The maximum occurrence of Co60 nuclei at 3.62 x 10^8 seconds is equivalent to about 11.46 years when the conversion factor of 3.16 x 10^7 seconds per year is applied.

Step-by-step explanation:

The maximum number of Co60 nuclei occurs at t = 3.62 x 108 seconds. To express this time in years, we can use the conversion factor that one year is equal to approximately 3.16 x 107 seconds. By dividing t by this conversion factor, we get:

t = 3.62 x 108 s / 3.16 x 107 s/year ≈ 11.46 years.

Therefore, the maximum number of Co60 nuclei occurs at about 3.62 x 108 seconds or approximately 11.46 years.

User Ben Lesh
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