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A 2.5 g copper penny is given a charge of 4.6 nc.

User Crowie
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Final answer:

The question pertains to the Physics concept of charge and the removal of electrons from a copper penny which results in a certain net charge of the penny.

Step-by-step explanation:

The question involves calculating the fraction of electrons removed from a copper penny when it is given a charge. In Physics, we often deal with the concept of charge, and copper being a conductor, can have its charge altered by the addition or removal of electrons. A 2.5 g copper penny given a charge of 4.6 nC implies a certain number of electrons have been either added to or removed from the penny.

To calculate the number of electrons involved, we use the fundamental charge of an electron, which is approximately 1.602 × 10−18 C. If we are given the charge in coulombs, we divide this by the charge of an electron to find the number of electrons that corresponds with that total charge.

Additionally, we might be interested in understanding the impact of these removed electrons on the overall mass of the penny. Although the mass change due to electron removal is typically negligible, calculations could be made to show this by considering the atomic mass of copper and the number of electrons usually present.

User Masterofdisaster
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