Question

what must the charge (sign and magnitude) of a particle of mass 1.50 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 700 n/c ?

Answer 1

The charge of the particle must be zero for it to remain stationary in the electric field of magnitude 700 N/C.

Step-by-step explanation:

To determine the charge of the particle, we can use the equation F = qE, where F is the force, q is the charge, and E is the electric field. Since the particle is stationary, the force on it must be zero. Therefore, we have 0 = q(700 N/C), where q is the charge we want to find. Solving for q, we get q = 0.

This means that the charge of the particle must be zero in order for it to remain stationary in the downward-directed electric field of magnitude 700 N/C.