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Write the formula of the conjugate base of each acid: HF, HPO42-, and CH3CH2OH. Be sure to answer all parts. HF - HPO42- - CH3CH2OH

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Final answer:

The conjugate base of an acid is formed when the acid donates a proton (H+) to a base. The formulas of the conjugate bases of HF, HPO42-, and CH3CH2OH are F-, PO43-, and CH3CH2O-, respectively.

Step-by-step explanation:

The conjugate base of an acid is formed when the acid donates a proton (H+) to a base. To find the formula of the conjugate base, we remove the proton from the acid.

For HF, the conjugate base is F-. Removing the H+ ion from HF leaves us with F-.

For HPO42-, the conjugate base is PO43-. Removing the H+ ions from HPO42- leaves us with PO43-.

For CH3CH2OH, the conjugate base is CH3CH2O-. Removing the H+ ion from CH3CH2OH leaves us with CH3CH2O-.

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