Question

Proteins A and B bind to each other to form a complex, AB. Under equilibrium the concentrations of A, B and AB are 10⁻² M. The dissociation constant of this reaction is

a) 10⁻⁴ M.
b) 10² M.
c) 1 M.
d) 10⁻² M
e) 10⁴ M

Answer 1

The dissociation constant of the reaction is 10^-2 M.

Step-by-step explanation:

The dissociation constant of a reaction represents the equilibrium constant for the reaction. In this case, the dissociation constant for the binding of proteins A and B to form the complex AB is equal to the concentration of A multiplied by the concentration of B, divided by the concentration of AB.

Therefore, the dissociation constant can be calculated as K = ([A] * [B]) / [AB]. Given that the concentrations of A, B, and AB are all 10^-2 M, the dissociation constant is (10^-2 * 10^-2) / 10^-2 = 10^-2 M.

So, the correct answer is d) 10^-2 M.