Final answer:
The pressure drop across the orifice is calculated using the manometer readings, the specific gravity of the manometer fluid, and the known density of mercury, factoring in the conversion between mm and cm and the constant of gravitational acceleration.
Step-by-step explanation:
To calculate the pressure drop across the orifice (ΔP) for each manometer reading in mm Hg, we use the fact that pressure is proportional to the height of the manometer fluid column (h), the density of the fluid (ρ), and the acceleration due to gravity (g).
Since the manometer fluid has a specific gravity (SG) of 1.10, its density is 1.10 times that of water, and for mercury, we use its density as a reference (ρ_Hg = 13.6 g/cm³). Given that 1 cm³ = 1 mL, the pressure drop can be calculated as ΔP = h ρ_mano g / ρ_Hg, where ρ_mano is the density of the manometer fluid. The gravitational acceleration (g) is approximately 9.81 m/s², and ρ_mano can be found by multiplying the SG of the manometer fluid by the density of water (1.00 g/cm³). Converting mm to cm and simplifying, the pressure drop for each reading can be computed.