Final answer:
To find the molarity of a 30 mg/L NaOH solution, first convert the mass to moles using the molar mass of NaOH (40.00 g/mol). Then, calculate moles (0.030 g / 40.00 g/mol = 0.00075 moles) and since the solution volume is 1 liter, the molarity is 0.00075 M.
Step-by-step explanation:
To determine the molarity of a sodium hydroxide (NaOH) solution with a concentration of 30 mg/L, we must first convert mass to moles using the molar mass of NaOH. The molar mass is calculated by summing the atomic weights of its constituent elements: Na (23 g/mol), O (16 g/mol), and H (1 g/mol), which totals 40.00 g/mol for NaOH.
The conversion from milligrams to grams and then to moles is as follows:
Convert the concentration from milligrams to grams: 30 mg is 0.030 grams.
Calculate the number of moles of NaOH: 0.030 g × (1 mol/40.00 g) = 0.00075 moles.
Since the concentration is given in mg/L, the volume of the solution is implied to be 1 liter, so the molarity is 0.00075 M.
In order to determine the molarity of a NaOH solution with a concentration of 30 mg/L, we need to convert the mass of NaOH to moles and then calculate the molarity using the volume of the solution. Firstly, we need to convert the mass of NaOH from milligrams to grams by dividing it by 1000. Then, we convert the mass of NaOH from grams to moles by dividing it by the molar mass of NaOH.
The molar mass of NaOH is calculated by adding up the atomic masses of Na (22.990 g/mol), O (15.999 g/mol), and H (1.008 g/mol) in NaOH.
Once we have the moles of NaOH, we can use the definition of molarity to calculate the molar concentration by dividing the moles of NaOH by the volume of the solution in liters.