Question

The energy (E) of a photon absorbed or emitted

by a body is proportional to its frequency (v).
E=hxv
The constant h equals 6.63 x 10-34 J.s. What is
the energy of a photon of microwave radiation
with a frequency of 3.20 X 10¹¹ s-¹?


Helppp please!!!

Answer 1

The energy of a photon of microwave radiation with a frequency of 3.20 × 10¹¹ Hz is 2.12032 × 10²² joules, calculated using Planck's constant and the equation E = hv.

Step-by-step explanation:

The energy of a photon can be calculated using the equation E = hv, where E is the energy of the photon in joules (J), h is Planck's constant, and v is the frequency of the radiation in hertz (Hz). Given that Planck's constant h is 6.626 × 10-34 J·s, and the frequency of the microwave radiation v is 3.20 × 1011 s-1, we can calculate the energy of a photon as follows:

E = h × v = (6.626 × 10-34 J·s) × (3.20 × 1011 Hz) = 2.12032 × 10-22 J

Therefore, the energy of a photon of microwave radiation with a frequency of 3.20 × 1011 Hz is 2.12032 × 10-22 joules.