195k views
3 votes
Sketch the region bounded by the curves y = 2x√x,y = 3, and y = 2/3 then find the volume of the solid generated by revolving the region about the x-axis.

a) 16π
b) 12π
c) 8π
d) 4π

User WLin
by
8.5k points

1 Answer

3 votes

Final answer:

To find the volume of the solid generated by revolving the region bounded by the curves about the x-axis, we can use the method of cylindrical shells.

Step-by-step explanation:

To find the volume of the solid generated by revolving the region bounded by the curves about the x-axis, we can use the method of cylindrical shells. First, let's find the points of intersection between the curves. Set the equations equal to each other:
2x√x = 3
Solving this equation, we get x = 27/8. Now, we can set up the integral to calculate the volume of the solid:

V = ∫27/832πx(3-(2/3))dx

Simplifying, we have:
V = 2π∫27/83 x(5/3) dx

Integrating, we get:
V = 2π(5/3) ∫27/83 x dx

By evaluating this integral, we find the volume to be 12π.

User Nejc Jezersek
by
7.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.