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73.5 mol of P₄O₁₀ contains how many moles of p ?

User Alger
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Final answer:

To find the number of moles of phosphorus (P) in 73.5 mol of P₄O₁₀, multiply 73.5 mol by the ratio 4 mol P / 1 mol P₄O₁₀ to get 294 mol P.

Step-by-step explanation:

To find the number of moles of phosphorus (P) in 73.5 mol of P₄O₁₀, we need to understand the ratio of P to P₄O₁₀. In the formula P₄O₁₀, there are 4 moles of P for every 1 mole of P₄O₁₀. Therefore, if we have 73.5 mol of P₄O₁₀, we can multiply that by the ratio 4 moles of P / 1 mole P₄O₁₀ to find the number of moles of P.



73.5 mol P₄O₁₀ * (4 mol P / 1 mol P₄O₁₀) = 294 mol P

User Fatih Bulut
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