Final Answer:
The electric field at the origin due to q1 and q2 is approximately
an angle of approximately 153.43 degrees below the positive x-axis.
Step-by-step explanation:
The electric field at the origin due to a point charge q can be calculated using the formula
where k is Coulomb's constant
|q| is the magnitude of the charge, and r is the distance between the charge and the point of interest.
For q1 at x = 1.95 m along the x-axis, the distance r1 between q1 and the origin (0,0) is calculated using the distance formula:

The electric field E1 at the origin due to q1 is given by

For q2 at y = 1.00 m along the y-axis, the distance r2 between q2 and the origin is

The electric field E2 at the origin due to q2 is

To find the net electric field at the origin due to q1 and q2, we consider their magnitudes and directions. Using vector addition
where θ is the angle between E1 and E2. Calculating this yields a magnitude of approximately
at an angle of approximately 153.43 degrees below the positive x-axis.