Question

2. a rectangular bar as a gold, has a length equals 2.00 cm, a width equals 2.00 cm, and a high equals 1.50 cm. what is the mass of this bar? (density of gold = 19.3 g/cm3 at 20°c.)?

Answer 1

The mass of the gold bar can be found using the formula m = pV, where m is the mass, p is the density, and V is the volume. Substituting the given values, we find that the mass of the gold bar is 115.8 grams.

Step-by-step explanation:

To find the mass of the gold bar, we can use the formula m = pV, where m is the mass, p is the density, and V is the volume. The density of gold is given as 19.3 g/cm³. The volume of the rectangular bar can be calculated as length x width x height, which is 2.00 cm x 2.00 cm x 1.50 cm = 6.00 cm³.

Substituting the values into the formula, we get m = 19.3 g/cm³ x 6.00 cm³ = 115.8 g.

Therefore, the mass of the gold bar is 115.8 grams.