Final answer:
The linear speed of a point on the edge of a flywheel with a radius of 20.0 cm and centripetal acceleration of 900.0 cm/s² is calculated using the relationship v = r ω, yielding a linear speed of 1.342 m/s.
Step-by-step explanation:
To calculate the linear speed (v) of a point on the rim of a flywheel, we can use the relationship between linear speed, radius (r), and angular speed (ω). The formula is v = r ω. Given the radius and the centripetal acceleration (ac), we first need to find the angular speed using the formula ac = r ω2. Rearranging this formula gives us ω = √(ac/r).
For the flywheel with a radius of 20.0 cm (0.2 m) and a centripetal acceleration of 900.0 cm/s2 (9 m/s2), we can find the angular speed as follows:
ω = √(9 m/s2 / 0.2 m) = √(45 s-2) = 6.708 s-1.
Then, we calculate the linear speed using the angular speed:
v = 0.2 m * 6.708 s-1 = 1.342 m/s.
So, the linear speed of a point on the edge of the flywheel is 1.342 m/s.