Final answer:
To find the parametric equations for a ray, you need a starting point and a direction vector. The starting point is given as (6, 8, 0) and we assumed an arbitrary direction vector, (1, 0, 0), since the direction '11' is unclear. Therefore, the parametric equations are x(t) = 6 + t, y(t) = 8, and z(t) = 0.
Step-by-step explanation:
To give parametric equations for the ray starting at the point (6, 8, 0), we need a direction vector. Since the direction is not clearly defined in the question, we will assume a generic direction vector δ = (dx, dy, dz). The parametric equations for a ray can be written as:
- x(t) = x0 + t*dx
- y(t) = y0 + t*dy
- z(t) = z0 + t*dz
Where (x0, y0, z0) is the starting point, t is the parameter (t ≥ 0 for a ray), and (dx, dy, dz) is the direction vector. Since the question provides the starting point (6, 8, 0) and asks for the direction of the vector 11 without further specification, we'll use an arbitrary direction vector, say (1, 0, 0), which is a unit vector along the x-axis.
The parametric equations for the ray in the direction of the vector 11 would then be:
- x(t) = 6 + t*1
- y(t) = 8 + t*0
- z(t) = 0 + t*0
Note that typically the direction vector should be specified or derived from context, which is not provided here.