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The plus of gold is 12.55 kj⋅mol−1 , and its δfus is 9.384 j⋅mol−1⋅k−1 . what is the melting point of gold??

User Teisman
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Final answer:

The melting point of gold can be calculated using the Clausius-Clapeyron relation, where the enthalpy of fusion (12.55 kJ/mol) is divided by the entropy change of fusion (9.384 J/mol∙K), resulting in a melting point of approximately 1337.856 Kelvins.

Step-by-step explanation:

To find the melting point of gold, we will use the Clausius-Clapeyron relation which relates the pressure and temperature to the enthalpy of fusion and the entropy change during the phase change:

∆H = T ∙ ∆S

Where ∆H represents the enthalpy of fusion, T is the temperature in Kelvin, and ∆S is the entropy change of fusion. Given that the enthalpy of fusion (∆Hfus) of gold is 12.55 kJ/mol and the entropy change of fusion (∆Sfus) is 9.384 J/mol∙K, we can rearrange the formula to solve for T as follows:

T = ∆Hfus / ∆Sfus

Now we can plug in the values:

T = (12.55 ∙ 103 J/mol) / (9.384 J/mol∙K)

T = 1337.856 K

This yields a melting point T of approximately 1337.856 Kelvins for gold.

User Patronaut
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