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A ferris wheel accelerates (from rest) such that the speed of its passengers increases by dv/dt = 6t ft/s2, where t is in seconds.?

User ShelbyZ
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Final answer:

The ferris wheel in this question accelerates with an increasing speed described by dv/dt = 6t ft/s². The velocity function is v(t) = 3t² ft/s and the position function is p(t) = t³ ft.

Step-by-step explanation:

The ferris wheel in this question is accelerating with an increasing speed of dv/dt = 6t ft/s², where t is in seconds.

To find the velocity as a function of time, we need to integrate the acceleration function. When we integrate 6t, we get 3t². So the velocity function is v(t) = 3t² ft/s.

To find the position as a function of time, we need to integrate the velocity function. When we integrate 3t², we get t³. So the position function is p(t) = t³ ft.

User HereHere
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