Question

Prove or give a counterexample to the statement that for any nez and aez, the equation x x = a hasat most two solutions in z.?

Answer 1

The statement that for any nez and aez, the equation xx = a has at most two solutions in z is false.

Step-by-step explanation:

To prove or give a counterexample to the statement that for any nez and aez, the equation xx = a has at most two solutions in z.

We can show that this statement is false by providing a counterexample. Consider the equation 4x^2 = 16. In this case, we have two solutions in z: z = 2 and z = -2.

Therefore, we have disproven the statement by providing a counterexample where the equation xx = a has more than two solutions in z.