Final answer:
The potential difference between two points A and B equidistant from charges is calculated. Given the symmetry, the potential difference is zero.
Step-by-step explanation:
The question is asking for the potential difference between two points in the vicinity of electric charges. Since the student has provided the size of the charges and the distances involved, we can apply the concept of electric potential (V) defined as V = k * (q / r), where 'k' is Coulomb's constant (8.99 x 10^9 N*m^2/C^2), 'q' is the charge, and 'r' is the distance from the charge to the point of interest.
To find the potential difference (Va - Vb), we need the potential at each point (Va and Vb) due to the charges. Since the distances ('a' and 'b') to the points A and B from each charge (q = 2.0 nc and q' = −3.0 nc) are the same, the effect of the charges would be identical at both points, resulting in a zero potential difference. This conclusion assumes a uniform field and that other charges in space do not alter the potential at points A and B.