Question

Give the general solution to y′=x3y3 4x3y2 y=−4 ce3/(4x4) y3=−4 ce1/(2x2) y2=4 cex2 y3=4 cex4 y3=−4 ce2x4/3?

Answer 1

The general solution to the differential equation y' = x^3y^3 - 4x^3y^2 is y = -4c*e^(3/(4x^4)), where c is a constant.

Step-by-step explanation:

The general solution to the differential equation y' = x^3y^3 - 4x^3y^2 is given by y = -4c*e^(3/(4x^4)), where c is a constant. This general solution includes several variations that can be obtained by changing the value of c.

For example, if c = 1, then the solution becomes y = -4e^(3/(4x^4)). If c = 2, then the solution becomes y = -4e^(6/(4x^4)). And so on.

Therefore, the general solution to the differential equation is y = -4c*e^(3/(4x^4)), where c can be any real number.