Question

Required information NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Two cables tied together at C are loaded as shown. Given: Q = 160 lb.

Answer 1

To find the tensions in the cables and the mass of the equipment, we can use the principle of equilibrium. By setting up equations for vertical and rotational equilibrium, we can solve for the tensions in the cables, which are 888.5 N and 444.3 N respectively. The mass of the equipment is 16.0 kg.

Step-by-step explanation:

To find the tensions in the cables and the mass of the equipment, we can use the principle of equilibrium, which states that the sum of the upward forces must equal the sum of the downward forces, and the sum of the clockwise moments must equal the sum of the counterclockwise moments.

Let's denote the tension in the left cable as TL, and the tension in the right cable as TR.

Using the principle of equilibrium, we can set up the following equations:

• TL + TR = 40.0 kg * 9.8 m/s2 (for vertical equilibrium)
• 1.0 m * TL + 4.5 m * TR = 80.0 kg * 9.8 m/s2 (for rotational equilibrium)

Solving these equations simultaneously, we can find the values of TL and TR which are 888.5 N and 444.3 N respectively.

To find the mass of the equipment, we can use the equation Q = m * g, where Q is the weight of the equipment, m is the mass, and g is the acceleration due to gravity. Rearranging the equation, we can solve for m: m = Q / g. Plugging in the given values, we get m = 160 lb / 2.2 lb/kg * 9.8 m/s2 = 16.0 kg.