Final answer:
To find the maximum length of aluminum foil that can be created from 1.09 kg, the mass must be divided by the density to determine volume, and then the volume divided by the product of the width and thickness to find the length in millimeters, which is then converted to meters.
Step-by-step explanation:
The question requires the calculation of the maximum length of foil that can be made from 1.09 kg of aluminum foil with dimensions and density provided. First, we need to convert the density from g/cm³ to g/mm³ since the thickness of the foil is given in mm. Density in g/mm³ is 0.0027 g/mm³ because 1 cm³ is equivalent to 1000 mm³. Then, we calculate the volume of foil that can be made from 1.09 kg (1090 g) by dividing the mass of the foil by its density (Volume = mass / density).
Volume = 1090 g / 2.7 g/cm³ = 1090 g / 0.0027 g/mm³ = 403,703.70 mm³.
Next, we find out how long a piece of foil we can make by dividing the volume by the cross-sectional area (the product of the width and thickness of the foil). The length of foil (L) can be calculated as L = Volume / (width x thickness).
L = 403,703.70 mm³ / (305 mm x 0.014 mm), which after doing the calculation, provides the answer in millimeters, and then we convert it to meters to match the answer choices.
The maximum length of foil that can be made from 1.09 kg of aluminum foil is therefore L meters.